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problem solving/Project Euler

Problem 48 - Find the last ten digits of 1^1 + 2^2 + ... + 1000^1000.

링크

The series, 1^(1) + 2^(2) + 3^(3) + ... + 10^(10) = 10405071317.

Find the last ten digits of the series, 1^(1) + 2^(2) + 3^(3) + ... + 1000^(1000).


python

c++