Problem 6 - What is the difference between the sum of the squares and the square of the sums?

링크

The sum of the squares of the first ten natural numbers is,

1² + 2² + ... + 10² = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)² = 55² = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

sum (k = 1~n) k = n * (n+1) / 2

sum (k = 1~n) k^2 = n * (n+1) * (2n+1) / 6

python 1

pow(sum([x for x in range(101)]), 2) - sum([x*x for x in range(101)])

python 2

pow((100*101/2),2) - (100*101*201/6)